Now how do we find out which reactant is which?
There are two ways: the first way is to convert both reactant to the same product and see which one produces the least, the second way is to convert one reactant to the other and see how much is needed to react with each other.
If you have 67.0g of Cl2 and 35.0g of O2 in the reaction 2Cl2 + O2 à2OCl2 which reactant is the limiting quantity?
67.0g Cl2 x 1 Mol Cl2 x 2 Mol OCl2 x 87.0g = 82.1 g of OCl2
71.0g 2 Mol CL2 1 Mol OCl2
44.0g O2 x 1 Mol O2 x 2 Mol OCl2 x 87.0g = 239 g of OCl2
32.0g 1 Mol O2 1 Mol OCl2
44.0g O2 x 1 Mol O2 x 2 Mol Cl2 x 71.0g = 195 g of Cl2
32.0g 1 Mol O2 1 Mol Cl2
Using the second way we can also determine how much excess we have or how much is missing for the whole reaction to occur.
195- 67= 128g
This means that 128g of Cl is missing.
Here is another example question and tutorial
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